the atomic number of beryllium is 4 while that of oxygen is 8 write down the electronic configuration of the two and deduce their valency from the same
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Beryillium ......2,2. and valency +2
Oxygen.......2,6...and valency _2.....
Oxygen.......2,6...and valency _2.....
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Be = 1s ^2 2s^2. valency = 2
O= 1s^2 2s^2 2p^4 valency =2
hope it will help you
O= 1s^2 2s^2 2p^4 valency =2
hope it will help you
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