Chemistry, asked by Sabbir4438, 1 year ago

The atomic number of beryllium is 4 while that of oxygen is 8 write down the electronic configuration of 2 and reduced their valency for the same

Answers

Answered by keshaw521
1
The electric configuration of 2 i.e, Helium is 0 and the valency will be also zero

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Answered by dryash1009
0

Answer:

Explanation:

Atomic number of Beryllium = 4

Electronic configuration = (2, 2)

Atomic number of Oxygen = 8

Electronic configuration = (2, 6)

Valency of Beryllium is 2,

Valency of Oxygen is = 8 ‒ 6 = 2

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