The atomic number of beryllium is 4 while that of oxygen is 8 write down the electronic configuration of 2 and reduced their valency for the same
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The electric configuration of 2 i.e, Helium is 0 and the valency will be also zero
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Answer:
Explanation:
Atomic number of Beryllium = 4
Electronic configuration = (2, 2)
Atomic number of Oxygen = 8
Electronic configuration = (2, 6)
Valency of Beryllium is 2,
Valency of Oxygen is = 8 ‒ 6 = 2
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