Question

The atomic number of four elements P, Q, R and S are 6, 10, 12 and 17 respectively. Write the formula of the ionic compound formed by reacting two elements.

Answer 1

Answer:

The atomic number of four elements P, Q, R and S are 6, 10, 12 and 17

The atomic numbers of four elements PQ,R and S are 6,10,12 and 17 respectively. The two elements that can combine to form covalent compounds are P (6= 2,4) and S (17= 2,8,7). So P needs 4 electrons to complete its octet which it shares with S which needs 1 electron to complete it.

Answer 2

Answer:

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The atomic numbers of four elements PQ,R and S are 6,10,12 and 17 respectively. The two elements that can combine to form covalent compounds are P (6= 2,4) and S (17= 2,8,7). So P needs 4 electrons to complete its octet which it shares with S which needs 1 electron to complete it.

In another words:

Electronegativity difference between P and R

Electronegativity difference =3.44−1.31=2.13

The electronegativity difference is greater 1.7 it shows ionic compound.