The average age of a father ,his mother and son 3years ago was 27 years and that of mother and son 5 years ago was 20 years.What is the fathers present age?
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let present age of
father be f,
mother be m, and
son be s
:. 5 yrs ago,
mother = m-5
son=s-5
:. average= 20
![\frac{m - 5 + s - 5}{2} = 20 \frac{m - 5 + s - 5}{2} = 20](https://tex.z-dn.net/?f=+%5Cfrac%7Bm+-+5+%2B+s+-+5%7D%7B2%7D+%3D+20)
m + s - 10 = 40
m + s = 50 ____(1)
before 3 yrs
mother = m -3
father =f-3
son = s-3
:. average = 27
![\frac{m - 3 + f - 3 + s - 3}{3} = 27 \frac{m - 3 + f - 3 + s - 3}{3} = 27](https://tex.z-dn.net/?f=+%5Cfrac%7Bm+-+3+%2B+f+-+3+%2B+s+-+3%7D%7B3%7D+%3D+27+)
:. m+ f+ s -9 = 27×3
f+ m+ s= 81+9
f+ 50= 90 [ bcs. m+s = 50.... by (1)]
f= 40
hence present age of father is 40 yrs.
hope it helps....
plz mark brainliest...
father be f,
mother be m, and
son be s
:. 5 yrs ago,
mother = m-5
son=s-5
:. average= 20
m + s - 10 = 40
m + s = 50 ____(1)
before 3 yrs
mother = m -3
father =f-3
son = s-3
:. average = 27
:. m+ f+ s -9 = 27×3
f+ m+ s= 81+9
f+ 50= 90 [ bcs. m+s = 50.... by (1)]
f= 40
hence present age of father is 40 yrs.
hope it helps....
plz mark brainliest...
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