Math, asked by talo5911, 1 year ago

The average age of a father ,his mother and son 3years ago was 27 years and that of mother and son 5 years ago was 20 years.What is the fathers present age?

Answers

Answered by KvKt2217
1
let present age of

father be f,

mother be m, and

son be s

:. 5 yrs ago,

mother = m-5

son=s-5

:. average= 20

 \frac{m - 5 + s - 5}{2} = 20

m + s - 10 = 40

m + s = 50 ____(1)

before 3 yrs

mother = m -3

father =f-3

son = s-3

:. average = 27

 \frac{m - 3 + f - 3 + s - 3}{3} = 27

:. m+ f+ s -9 = 27×3

f+ m+ s= 81+9

f+ 50= 90 [ bcs. m+s = 50.... by (1)]

f= 40

hence present age of father is 40 yrs.

hope it helps....

plz mark brainliest...
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