Question

The average ages of three persons is 27 years. Their ages are in the proportion of 1:3:5.What is the age in years of the youngest one among them.

Answer 1

let x be the common multiple
$1x + 3x + 5x = 27 \\ 9x = 27 \\ x = 3$
x=3 years
3x= 3×3 = 9 years
5x= 5×3 = 15 years
the youngest among them age is 3 years
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Answer 2

Given:

Average of ages of three persons=27

Ratio of ages of three person=1:3:5

To find:

Age of youngest person among them.

Solution:

Let age of one person=x

Age of second person=3x

Age of third persons=5x

According to question

$\frac{x+3x+5x}{3}=27$

$\frac{9x}{3}=27$

$3x=27$

$x=\frac{27}{3}=9$

Age of one person=9 years

Age of second person=3x=$3\times 9=27years$

Age of third persons=$5x=5\times 9=45 years$

Age of youngest person=9 years