Question

the average atomic mass of a sample of an element element X is 16.2 u. What are the percentage of isotope 816 X and 818 k in this sample

Answer 1

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Answer 2

let% of first isotope(mass no.=16) be x and second(mass no.=18) be100-x

Avg. atomic mass=(16× x/100+ 18×100-x/100)

                     16.2    =(16x/100+ 1800-18x/100)

                      16.2    =(16x+1800-18x/100)

                       16.2   =-2x+1800/100

                  16.2×100= -2x+1800, 1620-1800= -2x

           -2x= -180, x=90, so ist iso. %= x=90%, 2nd iso %= 100-x=100-90= 10%