The average atomic mass of an element X is 16.2 units.What is the percentage of isotope for 168 X and 188 X in the sample
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let atomic mass of 16 is (x) and 18 is (100-x).
so equation=16*x+18*(100-x)/100=16.2
16x+1800-18x=1620
-2x=-180
x=90%
100-x=10%
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