Question

The average force necessary to stop a bullet of mass 20g moving with a speed a speed of 250m/s as it peneterates into the wood for a distance of 12 cm is

Answer 1

Explanation:

Answer

v^2 =u^2 - 2as

0 = (250 )^2 - 2*0.12*a

0.24a=62500

a= 62500/0.24

now

F = ma

= 20/1000 * 62500/0.24

solve it

F = 5208 N Hope this would be helpful