The average force necessary to stop a hammer with 25NS momentum in 0.04second is
Answers
Answered by
1
Answer:
Impulse=Force× time
Force=impulse÷time
=25÷0.04
=625 N
Answered by
1
Answer:
625 N
explanation-
F=momentum÷time
F=25÷0.04
=625N
Similar questions