Question

The average IQ of 10 students in a mathematics course is 114. If 9 of the students have IQs of 101, 125, 118, 128, 106, 115, 99, 118, and 109, what must be the other IQ?

Answer 1

Answer:

121

Step-by-step explanation:

Number of students -10

Average IQ- 114

Total of 10=114*10=1140

Total of 9 is: 101+125+118+128+106+115+99+118+109=1019

The remaining IQ = 1140-1019=121

Answer 2

Given,

The average IQ of 10 students is 114.

The Iq of 9 students is 101, 125, 118, 128, 106, 115, 99, 118, and 109.

To Find,

The IQ of the other student.

Solution,

The formula for calculating the average is

Average = Sum of observations/Number of observations.

Let the IQ of 10th student be x

Average of IQ of 10 students = 114

(101+125+118+128+106+115+99+118+109+x)/10 = 114

1019+x = 1140

x = 121

Hence, the IQ of the other student is 121.