Question

The average length of the double helix in human chromosome is 5 cm.
a. Approximately how many base pairs would be present in such a chromosome?
b. If all chromosomes of the human complement were 5 cm in length, approximately how many base pairs would be present in sperm nucleus?​

Answer 1

Answer:

Option B is correct

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Answer 2

Answer will be for a. 147,058,823

b. 3,382,352,941

Explanation:

• a. length of the double helix DNA = no. of base pairs× 0.34nm
• distance between two base pair is 0.34 nm. length of the DNA 5cm or 50000000nm
• No. of base pairs= length of the DNA÷ 0.34nm
• No. of  base pairs= 50000000÷0.34≈1,47,058,823bp
• single chromosome contain 1,47,058,823bp
• b. sperm nucleus contain 23 chromosomes. so the number of base pairs would be present in sperm nucleus will be 23×1,47,058,823=3,382,352,941bp