The average mark of candidates in an aptitude test was 128.5 with a standard deviation of 8.2.Three scores extracted for the test are 148,102,152,what is the average of the extract scores that are extreme values (outliers)
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The average of the extracted scores that are extreme values is 102
Step-by-step explanation:
Given average mark of candidate (Mean) = 128.5
Standard Deviation = 8.2
As per mean and standard deviation method, the extreme values (outliers) are beyond the range
Mean ± 3 × Standard Deviation
This range will be
128.5 - 3 × 8.2 to 128.5 + 3 × 8.2
= 103.9 to 153.1
The three scores extracted are 148, 102, 152
Out of these three scores only 102 is beyond the range above
Therefore, only 102 is the outlier
The average will be 102 only.
Hope this answer is helpful.
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