the average mass that must be lifted by a hydraulic press is 80 kg. If the radius of the larger piston is 5 times that of the smaller piston. What is the mimimum force that must be applied?
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Answered by
24
using Pascal law
A₂=5A₁
F₂=80 ×9.8
F₁ / A₁ =F₂ /A₂
F₁= 8 ×98 / 5
F₁=156.8 N
A₂=5A₁
F₂=80 ×9.8
F₁ / A₁ =F₂ /A₂
F₁= 8 ×98 / 5
F₁=156.8 N
Answered by
4
Answer:31.4 N
Explanation:
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