Question

The average molecular mass of mixture of gas containing nitrogen and carbon dioxide is 36. The mixture contain 280gm of nitrogen therefore the amount of carbon dioxide present in mixture is...

Answer 1

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Answer 2

Answer:

The amount of carbon dioxide present in mixture is 293.04 g.

Explanation:

The moles of nitrogen gas $\frac{280 g}{28 g/mol}=10 mol$

Moles of carbon dioxide = x

mole fraction of nitrogen gas =$\chi_1=\frac{10}{10+x}$

Mole fraction of carbon-dioxide gas $\chi_2=\frac{x}{10+x}$

Average molecular mass of gases:

$M_{avg}=\sum\chi_i\times M_i$

$36=\frac{10}{10+x}\times 28+\frac{x}{x+10}\times 44$

$x=6.66 moles$

Mass of 6.66 moles of carbon-dioxide:

$6.66\times 44 g/mol=293.04 g$

The amount of carbon dioxide present in mixture is 293.04 g.