Question

the average number of Printing errors in book of 512 pages is 4. if total number of printing errors in the first 302 pahes in 1208, then average number of printing errors in remaing pages is:​

Answer 1

Step-by-step explanation:

It is given that the total number of pages are 512

and errors on 302 pages is 1208

Hence, errors on each page=1208/302=4

Remaining pages = 210

Therefore remaining average errors = 210*4= 840

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Answer 2

The average number of printing errors in remaining pages is 4

Given :

• The average number of Printing errors in book of 512 pages is 4.

• The total number of printing errors in the first 302 pages in 1208

To find :

The average number of printing errors in remaining pages

Solution :

Step 1 of 3 :

Find total number of Printing errors in the book

Here it is given that average number of Printing errors in book of 512 pages is 4

So total number of Printing errors in the book

= 512 × 4

= 2048

Step 2 of 3 :

Find total number of printing errors in remaining pages

The total number of printing errors in the first 302 pages in 1208

So total number of printing errors in remaining pages

= 2048 - 1208

= 840

Step 3 of 3 :

Find average number of printing errors in remaining pages

Remaining number of pages = 512 - 302 = 210

The average number of printing errors in remaining pages

$\displaystyle \sf{ = \frac{840}{210} }$

$\displaystyle \sf{ = 4 }$

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