The average of 10 terms and12 terms of an AP is 12 and14 respectively. 5^th term ofthe progression will be?
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Answer:
11
Step-by-step explanation:
Average of ten terms= 12
Sum of 10 terms =120
120=5(2a+9d)
2a+9d=24---------------------------1
Average of 12 terms =14
sum of 12 terms =168
168=6(2a+11d)
168/6=2a+11d
2a+11d=28--------------------------2
subtract equation 1 from 2
2a + 11d =28
-2a +-9d=-24
-------------------
2d=4
d=2
substitute d=2 in equation 1
2a + 9*2= 24
2a+18=24
2a =6
a= 3
a=3 d=2 n=5 an=?
an= a+(n-1)d
= 3+(5-1)2
=3+4*2
=3+8
an=11
Therefore the 5th term of the AP is 11
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