Math, asked by faizatg8978, 1 year ago

The average of 11 results in 50. If the average of first six results is 48 & that of last six 51, the sixth result is?
A) 44
B) 50
C) 56
D) 48

Answers

Answered by diro101
10

Answer:

56

Step-by-step explanation:

total sum of 11 results: 11*50 => 550

total sum of first 6 results:  6*49 => 294

total sum of last 6 results: 6*52=> 312

sixth result would be 294+312-550 => 56

Answered by wifilethbridge
2

The sixth term is 44

Step-by-step explanation:

Average =\frac{\text{Sum of all observations}}{\text{No. of observations}}

The average of 11 results in 50.

So, 50=\frac{\text{Sum of 11 observations}}{11}\\50 \times 11=\text{Sum of 11 observations}\\550=\text{Sum of 11 observations}

The average of first six results is 48

48=\frac{\text{Sum of first 6 results}}{6}\\48 \times 6 = \text{Sum of first 6 results}\\288 = \text{Sum of first 6 results}

The average of last six results is 51

51=\frac{\text{Sum of last 6 results}}{6}\\51 \times 6 = \text{Sum of last 6 results}\\306= \text{Sum of last 6 results}

Six term =  (Sum of first 6 terms +Sum of last six terms)-Total sum of 11 terms

Six term = (306+288)-550=44

Hence The sixth term is 44

#Learn more :

The average of 11 result is 50.if average of first 6 is 62 and that of last six is 49.find sixth result

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