Math, asked by amishubhi9853, 11 months ago

The average of 13 numbers is 20.If the average of first 6numbers is 18 and that of the last 6numbers is 21 find the 7th number

Answers

Answered by venupillai
1

Answer:

The 7th number is 26

Step-by-step explanation:

Average = Sum of observations / No. of observations

The average of all 13 numbers = 20

=> Sum of the 13 numbers (S) = 13*20 = 260

=> S = 260

Average of first 6 numbers = 18

=> Sum of first 6 numbers (S1) = 6*18 = 108

=> S1 = 108

Average of last 6 numbers = 21

=> Sum of last 6 numbers (S2) = 6*21 = 126

=> S2 = 126

Let "x" be the unknown 7th number.

Clearly,

S = S1 + x + S2

260 = 108 + x + 126

260 = 234 + x

x = 260 - 234

x = 26

Check:

The sum of all 13 numbers = 108 + 26 + 126 = 260

Average of 13 numbers = 126/13 = 20

Answered by chowdhurysayoni31
0

Answer:

18

Step-by-step explanation:

let the first six numbers be a, b, c, d , e, f

therefore

a+b+ c+ d + e + f/6=18

or, a+b+ c+ d + e + f=108

And,

let the last six numbers be h,i,k,l,m,n

we know,

h+i+k+l+m+n/6= 21

or, h+i+k+l+m+n=126

therefore

let g be the 7 th no.

and g= 126-108= 18

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