The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
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Answer:
19
Step-by-step explanation:
Let x be the sum of 20 no.s
AVERAGE=x/20
for avg = 0; x must be equal to 0
thus at least 1 no. must be -ve so that sum comes = 0
there can be at the most 19 no.s greater than 0
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