Question

using remainder theoram find the remainder when p(x) is divided by g(x) , p(x)=x^3-6x^2+9x+3 ,g(x) = x-a​

Answer 1

Answer: The remainder is a^3-6a^2+9a+3

Step-by-step explanation:

Zero of ye polynomial g(x)=>x-a=0=>x=a

According to Remainder Theorem, if p(x) is divided by g(x)=x-a the remainder will be p(a).

So, p(a)= a^3-6a^2+9a+3.