Math, asked by sonumangotra7338, 10 months ago

The average of 41 consecutive odd numbers is 49. What is the largest number.

A) 89 B) 91 C) 93 D) 95

Answers

Answered by pallavisami
0

Answer:

CORRECT OPTION IS A) 89

Step-by-step explanation:

Let x is first odd number

Then, x , x + 2, x + 4, x + 6, x + 8, ........... x + 2 × (41 - 1)

e.g., 41 consecutive odd numbers are : x , x + 2, x + 4, x + 6, ........... x + 80

now, sum of 41 consecutive odd numbers = (x + x + 2 + x + 4 + x + 6 + ..... + x + 80)

= 41x + (2 + 4 + 6 + 8 + 10 + 12 + ..... + 80)

= 41x + 40/2(2 + 80)

= 41x + 20 × 82

= 41x + 1640

Now, average of 41 consecutive odd numbers = sum of observations/total number of observations

49 = (41x + 1640)/41

49 = x + 40

x = 9

Hence, largest odd number = x + 80 = 89

Answered by Lueenu22
0

Answer:

your answer is option A(89)

Step-by-step explanation:

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