Question

The average of 5 consecutive integers is 4. Find the average of the squares of these integers

Answer 1

Answer: 18

Step-by-step explanation:

Let the 5 consecutive integers be:

X , X+1 , X+2, X+3, X+4

Average = 4

Average = Sum/Number of terms

Sum = 5X + 10

4 = (5X+10)/5

5X+10 = 20

5X = 10

X = 2

Numbers are: 2 , 3 , 4, 5 , 6

Squares of these: 4 , 9 , 16 , 25 , 36

Average = 90/5 = 18