Question

The average of 5 consecutive natural numbers is 43.find out the large number

Answer 1

Hey mate!!!


Let the first number be x
second x +1
third x + 2
fourth x + 3
fifth x + 4

Here largest is fifth that is x + 4. So we have to find it.

Given average is 43
=>
$\frac{x + x + 1 + x + 2 + x + 3 + x + 4}{5} = 43$
=>
$x + x + 1 + x + 2 + x + 3 + x + 4 = 215 \\ 5x + 10 = 215 \\ 5x = 215 - 10 \\ 5x = 205 \\ x = 205 \div 5 \\ x = 41$
so x is 41
then largest = x + 4
=>41 + 4
= 45


Largest is 45


Hope it helps dear friend ☺️✌️✌️