the average of 5 consecutive numbers is 14. find the 5 numbers.
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Given,
X¯=13
Let 5 consecutive numbers be x−2,x−1,x,x+1,x+2
((x−2)+(x−1)+x+(x+1)+(x+2))5=13
5x5=13
x=13
The AM of first 4 of these integers is,
((x−2)+(x−1)+x+(x+1))4
(4x−2)4
2x−12
We know x=13
2⋅13−12
252
12.5
The average of the first 4 of these integers is 12.5
Answered by
0
Answer:
70,71,72,73,74
Step-by-step explanation:
x+x+1+x+2+x+3+x+4/5=14
x+x+1+x+2+x+3+x+4=80
5x+10=80
x=70
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