Question

The average of 5 consecutive numbers is 50, then difference between "product of largest and smallest number with "product of fourth and second number is:​

Answer 1

Answer:

here your ansanswer

let the no.

x, x+1,x+2,x+3,x+4

ATQ

(x+x+1+x+2+x+3+x+4)/5=50

5x+10=250

5x=240

x=240/5=48

the no. are

48,49,50,51,52

atq

difference between "product of largest and smallest number with "product of fourth and second number is

52×48-51×49=2496-2499=-3

Answer 2

Answer:

The difference is -3

Step-by-step explanation:

let the five consecutive numbers be (x-2),(x-1),x,(x+1),(x+2).

*Average =sum of all numbers/total no. of numbers

50 =(x-2),(x-1),x,(x+1),(x+2) /5

50*5 =(x-2),(x-1),x,(x+1),(x+2)

250 =5x

x= 250/5

x= 50

the five consecutive numbers are 48,49,50,51,52.

difference between product of largest and smallest number with product of fourth and second number =(52*48) - (49*51)

= 2496 - 2499

= -3