Question

The average of 5 consecutive odd numbers a, b, c, d and e is 47. what is the product of a and d

Answer 1

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Answer 2

Answer:

2,107 is the value of product of 'a' and 'd'.

Step-by-step explanation:

Explanation:

Given , average of 5 consecutive odd numbers a, b , c, d and e = 47 .

Average  - The arithmetic mean is calculated by adding a set of numbers, dividing by their count, and then taking the result.

Let  the first odd number a be x .

So, according to the question 5 consecutive numbers are,

x , (x + 2) , (x + 4 ), ( x+ 6) and (x + 8)

Step 1:

From the question average of 5 consecutive odd numbers = 47

⇒$\frac{a + b+ c+ d + e}{5} = 47$

⇒a + b+ c + d+ e = 47 × 5 = 235

⇒x + ( x+ 2) + (x+ 4) + (x+ 6) + (x + 8) = 235

⇒5x + 20 = 235

⇒ 5x = 235 - 20 = 215

⇒ x = $\frac{215}{5}$ = 43 .

So, the first consecutive odd number (a) is 43 .

Therefore, 5 consecutive numbers are ,

a = 43 , b = (x + 2) = 45 , c = (x + 4 ) = 47 ,d = (x + 6) = 49 and e= (x + 8) = 51

Step 2:

So, from step 1 value of a is 43 and value of d is 49 .

Therefore, the product of a and d  is,

a × d = 43 × 49 = 2,107.

Final answer:

Hence, the product of a and d is 2,107 .

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