the average of 5 consecutive odd numbers abcd and e is 45 what is the product of b and d
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Hey,
Thanks for asking this question.
First of five consecutive odd numbers = a
So the next 4 consecutive odd numbers are,
b = a+2
c = a+4
d = a+6
e = a+8
Since average of these 5 numbers is 45,
=> ( a + a+2 + a+4 + a+6 + a+8 ) / 5 = 45
=> 5a + 20 = 45×5
=> 5a + 20 = 225
=> 5a = 205
=> a = 41
=> b = 43
=> c = 45
=> d = 47
=> e = 49
●●●So the product of b and d = 43×47 = 2021
■■■Hope my answer helped.
Thanks for asking this question.
First of five consecutive odd numbers = a
So the next 4 consecutive odd numbers are,
b = a+2
c = a+4
d = a+6
e = a+8
Since average of these 5 numbers is 45,
=> ( a + a+2 + a+4 + a+6 + a+8 ) / 5 = 45
=> 5a + 20 = 45×5
=> 5a + 20 = 225
=> 5a = 205
=> a = 41
=> b = 43
=> c = 45
=> d = 47
=> e = 49
●●●So the product of b and d = 43×47 = 2021
■■■Hope my answer helped.
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