The average of 5 even consecutive number is 112.what is the largest number?show the solution and answer
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Solution :-
Let the 5 consecutive even numbers be (x), (x + 2), (x + 4), (x + 6) and (x + 8) respectively.
According to the question.
⇒ (x + x + 2 + x + 4 + x + 6 + x + 8)/5 = 112
⇒ 5x + 20 = (5*112)
⇒ 5x + 20 = 560
⇒ 5x = 560 - 20
⇒ 5x = 540
⇒ x = 540/8
⇒ x = 108
Hence, the 5 consecutive even numbers are
= 108, 110, 112, 114 and 116.
116 is the largest among them.
Answer.
Let the 5 consecutive even numbers be (x), (x + 2), (x + 4), (x + 6) and (x + 8) respectively.
According to the question.
⇒ (x + x + 2 + x + 4 + x + 6 + x + 8)/5 = 112
⇒ 5x + 20 = (5*112)
⇒ 5x + 20 = 560
⇒ 5x = 560 - 20
⇒ 5x = 540
⇒ x = 540/8
⇒ x = 108
Hence, the 5 consecutive even numbers are
= 108, 110, 112, 114 and 116.
116 is the largest among them.
Answer.
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