Question

the average of 6 consecutive positive even integers is 15 the sum of the greatest and the least is how many times their average​

Answer 1

Answer:

Make x the first integer. This means the next integer will be x+1 , the one after that will be x+2 etc.

The average of a series of values is the sum of the values divided by the number of values, therefore:

x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)6=18.5

Adding the x s and numbers together:

6x+156=18.5

Re-arranging for x :

18.5×6=111=6x+15

111−15=6x

966=x

x=16

Subbing this into an expression for the first five integers (same process used at the start):

5x+105=y

(5×16)+105=y

y=18

Therefore, the average of the first five integers is 18.