Math, asked by dgulati1620, 1 year ago

The average of 7 numbers is 52. If 5 new numbers with sum of deviation 17 from average are included and 3 numbers 56 57 51 are excluded then find the average

Answers

Answered by sushmitha1427
0

What is the 6th number if the average of the first five is 54, and the last three is 52.? The average of all nine numbers is 50.

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Average of first 5 numbers =54 , Then sum of this 5 numbers = 54*5 =270.

The average of last 3 numbers = 52 . Sum of last 3 numbers = 52*3 = 156

The average of all 9 numbers =50 . The sum of all 9 numbers = 50*9 =450.

The required 6th number = sum of all 9 numbers -(sum of first 5 numbers + sum of last 3 numbers)

= 450 -(270+156)

= 450 - 426

=24

Answered by sonuvuce
1

Answer:

The new average is 53

Step-by-step explanation:

Average of 7 numbers = 52

The total value of the 7 numbers =52\times 7=364

Total value of the 5 new numbers added will be

= 5\times 52+\text{ sum of deviations}

= 260+17

= 277

The sum of the value of the three numbers removed

= 56+57+51

= 164

Now the total numbers =7+5-3=9

Total value =364+277-164=477

New Average =\frac{477}{9}=53

Hope this helps.

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