The average of 7 numbers is 60. The average of the first three numbers is 50, while the average of the last three is 70. What must be the remaining number?
1) 75 2) 65 3) 60 4) 55
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➡HERE IS YOUR ANSWER⬇
Average of 7 numbers being 60, the sum of the 7 numbers be (7×60) = 420.
Average of first 3 numbers being 50, the sum of first 3 numbers be (3×50) = 150.
Average of last 3 numbers being 70, the sum of last 3 numbers be (3×70) = 210.
Therefore, the remaining number
= Sum of 7 numbers - (sum of 1st 3 numbers + sum of last 3 numbers)
= 420 - (150+210)
= 420 - 360
= 60 .....(3) option
⬆HOPE THIS HELPS YOU⬅
Average of 7 numbers being 60, the sum of the 7 numbers be (7×60) = 420.
Average of first 3 numbers being 50, the sum of first 3 numbers be (3×50) = 150.
Average of last 3 numbers being 70, the sum of last 3 numbers be (3×70) = 210.
Therefore, the remaining number
= Sum of 7 numbers - (sum of 1st 3 numbers + sum of last 3 numbers)
= 420 - (150+210)
= 420 - 360
= 60 .....(3) option
⬆HOPE THIS HELPS YOU⬅
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