Question

the average of 8 numbers is 56.three of them are 49, 57 and 72.find the average of the remaining 5 numbers

Answer 1

Answer:

59

Step-by-step explanation:

(49+57+72+a+b+c+d+e)/8=56

49+57+72+a+b+c+d+e=448

178+a+b+c+d+e=448

a+b+c+d+e=448-178=270

(a+b+c+d+e)/5=270/5=56

Answer 2

Answer:

56

Step-by-step explanation:

Given:- Average of 8 numbers = 56

and given first 3 numbers are ( 49,57,72)

The total sum of 8 numbers=56 x 8 =448

→ Sum of first 3 numbers = 49+57+72 = 178

So, Average of other 5 numbers =

$\frac{270}{5} = 54$

Now Verification

178+270 = 448/8 = 56