the average of a set of 5 consecutive numbers a b c d and e is 51 what is the product of a and d?
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b=a+1
C=a+2 etc
(consecutive numbers)
Therefore
a+a+1+a+2+a+3+a+4/5=51
5a=225-10
5a=215
a=43
d=a+4=47
a*d=43*47
=2021
b=a+1
C=a+2 etc
(consecutive numbers)
Therefore
a+a+1+a+2+a+3+a+4/5=51
5a=225-10
5a=215
a=43
d=a+4=47
a*d=43*47
=2021
gj5:
my obtained answer is 2548
but I think its 2021
where is your method different from mine
wait i show you how I've done it
5 consecutive no. i.e. a,a+1,a+2,a+3,a+4
5a+10/5=51
5a+10=255
a=49
so when a=49 then d=52
and a*d= 2548
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