The average of eight numbers is 20. If one number 15 of them is replaced by 31, then the average will be
Answers
Answered by
0
Average = Sum of eight numbers / Total numbers
Therefore
20 = n1 + n2 + n3 +n4 + n5 + n6 + n7 + n8 / 8
20 = n1 + n2 + n3 +n4 + n5 + n6 + n7 + 15 / 8
160 = n1 + n2 + n3 +n4 + n5 + n6 + n7 + 15
160 - 15 = n1 + n2 + n3 +n4 + n5 + n6 + n7
145 = n1 + n2 + n3 +n4 + n5 + n6 + n7 ...(1)
Now if one number is 31 then
Average = n1 + n2 + n3 +n4 + n5 + n6 + n7 + 31 / 8
= 145 + 31 /8 ( from ..(1) )
= 176 / 8
= 22
Therefore
20 = n1 + n2 + n3 +n4 + n5 + n6 + n7 + n8 / 8
20 = n1 + n2 + n3 +n4 + n5 + n6 + n7 + 15 / 8
160 = n1 + n2 + n3 +n4 + n5 + n6 + n7 + 15
160 - 15 = n1 + n2 + n3 +n4 + n5 + n6 + n7
145 = n1 + n2 + n3 +n4 + n5 + n6 + n7 ...(1)
Now if one number is 31 then
Average = n1 + n2 + n3 +n4 + n5 + n6 + n7 + 31 / 8
= 145 + 31 /8 ( from ..(1) )
= 176 / 8
= 22
ShubhGandhi2903:
hope you like ir
Similar questions
Environmental Sciences,
6 months ago
Math,
6 months ago
Math,
1 year ago
Math,
1 year ago
Math,
1 year ago