The average of five consecutive even numbers is 30. What is the
sum of the smallest and the largest among these numbers?
a) 62
b) 60
c) 64
d) 68
Answers
Sum of the smallest and the largest is 60 if the average of five consecutive even numbers is 30
Given:
The average of five consecutive even numbers is 30
To Find:
The sum of the smallest and the largest among these numbers
Solution:
Assume that five consecutive even numbers are
a- 4 , a - 2 , a , a + 2 , a + 4
Sum of all the numbers = a - 4 + a - 2 + a + a + 2 + a + 4 = 5a
Average = 5a/5 = a
Average = 30
=> a = 30
Sum of smallest and largest = a - 4 + a + 4 = 2a
Substitute a = 30
2a = 2(30) = 60
Hence, sum of the smallest and the largest is 60
Correct option is b) 60
The sum of the smallest and the largest among these numbers = 60
Given :
The average of five consecutive even numbers is 30.
To find :
The sum of the smallest and the largest among these numbers is
a) 62
b) 60
c) 64
d) 68
Solution :
Step 1 of 4 :
Calculate the sum of five consecutive even numbers
Here it is given that the average of five consecutive even numbers is 30.
∴ The sum of five consecutive even numbers
= 5 × 30
= 150
Step 2 of 4 :
Form the equation to find the numbers
Let five consecutive even numbers are x , x + 2 , x + 4 , x + 6 , x + 8
By the given condition
Step 3 of 4 :
Find the numbers
So five consecutive even numbers are 26 , 28 , 30 , 32 , 34
Step 4 of 4 :
Calculate the sum of the smallest and the largest among these numbers
The smallest among these numbers = 26
The largest among these numbers = 34
The sum of the smallest and the largest among these numbers
= 26 + 34
= 60
Hence the correct option is b) 60
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