Question

The average of five numbers is 496. If two of them are 117
and 140, find the average of remaining three numbers.​

Answer 1

Answer:

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Step-by-step explanation:

Let five observations are ; a, b, c, d, and

e

given, average = 496

we know, average = sum of observations/ total number of observations

496 = (a + b + c+d + e)/5

a + b +c +d+ e = 496 x 5 = 2480 =

a/c to question, two observations are 117 and 140.

Let a = 117 and b = 140

then, 117 + 140 + c+ d + e =2480

c + d + e = 2480 - (117 + 140)

c+ d + e = 2480 - 257 = 2223

now, average of remaining three observations

= (c + d + e)/3

(2223)/3

= 741

Answer 2

Answer:

741

Step-by-step explanation:

Average of 5 numbers

= sum of 5 numbers /5

Sum of 5 no. = 496x5 = 2480

If two no. are 117 and 140

Sum of remaining 3 no. = 2480 - 257

= 2223

Average of remaining 3 no. = 2223/3

= 741