the average of four consecutive even number is 23 . Find the least number
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x+(x+2)+(x+4)+(x+6)=23*4
4x+12=23*4
4x=92-12
4x=80
x=20
so least number will be 20
4x+12=23*4
4x=92-12
4x=80
x=20
so least number will be 20
Answered by
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Let the four consecutive even numbers be x-3, x-1, x+1, x+3 respectively.
As their average is 27, we can write
[(x-3)+(x-1)+(x+1)+(x+3)] / 4 =27
→ (4x)/4 =27
→ x =27
So the largest number is,
x+4 = 27+3 =30
As their average is 27, we can write
[(x-3)+(x-1)+(x+1)+(x+3)] / 4 =27
→ (4x)/4 =27
→ x =27
So the largest number is,
x+4 = 27+3 =30
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