Math, asked by honeysmily140, 5 hours ago

The average of four positive
integers is 124.5. The highest
integer is 251 and the lowest
integer is 65. The difference
between the remaining two
integers is 26. Which of the
following integers is higher of
the remain-ing two integers?
Select one
a. 78
b. 102
c. 104
d. 100​

Answers

Answered by Anonymous
1

104

STEP BY STEP

Sum of four integers = 124.5 × 4 = 498

Let the required integers be x and x -26

Then, x + (x - 26) = 498 - (251 + 65)

⇒ 2x - 26= 182

⇒ 2x = 208

⇒ x = 104

Hence, required integer = 104

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