Question

The average of marks obtained by77 candidates in a certain examination is 17 ,if the average marks of faioed candidates is8 and passed candidates is 19 then find the number of passed candidates in examination

Answer 1

Answer:

The required number of passed candidates in the examination is $63$.

Explanation:

Concept:

In mathematics, an expression that incorporates variables, constants, and algebraic operations is known as an algebraic expression (addition, subtraction, etc.).

Given:

The average of marks obtained by $77$ candidates in a certain examination is $17$.

The failed candidates are $8$

The passed candidates are $19$

To find:

The objective is to find out the number of passed candidates in examination.

Solution:

Let the number of the passed candidates $x$

Then the number of the failed candidates$=77-x$

Now the total of marks obtained by $77$ candidates

$=77$ × $17$

$=1309$

The total of the marks obtained by passed candidates $=19$ × $x$$=19x$ and

the total of the marks obtained by failed candidates $=(77-x)$ × $8=1309$

Then the total$=19x+(77-x)$ × $8=1309$

⇒ $19x+616-8x=1309$

⇒ $11x=1309-616$

⇒ $11x=693$

⇒ $x=63$

Therefore, the required number of passed candidates in the examination is $63$.

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