Question

The average of marks of 17 students in an examination was calculated as 71. But it was later found that the mark of one student had been wrongly entered as 65 instead of 56 and another as 24 instead of 50. The correct average is

Answer 1

Answer:

i think correct ans is 72...

Step-by-step explanation:

17×71=1207

56-65=-9

50-24=26

-9+26=17

1207+17=1224

1224÷17=72...

Answer 2

The correct average is 72

Step-by-step explanation:

$Average = \frac{\text{Sum of all observations}}{\text{No. of observations}}$

We are given that The average of marks of 17 students in an examination was calculated as 71

So, $71 = \frac{\text{Sum of all marks}}{17}\\71 \times 17 = \text{Sum of all marks}\\1207= \text{Sum of all marks}$

Now we are given that the mark of one student had been wrongly entered as 65 instead of 56 and another as 24 instead of 50.

So, New sum = 1207-(65+24)+(56+50)=1224

So, New average = $\frac{1224}{17}=72$

Hence the correct average is 72

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