The average of N numbers is x. If each number is doubled, find the new average.
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(n1+n2+.....+N times)/N=x
then
(2n1+2n2+.....N times)/N=2*(n1+n2+.....N times)/N
=2x
then
(2n1+2n2+.....N times)/N=2*(n1+n2+.....N times)/N
=2x
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