The average of six numbers is 30. If the average of first four is 25 and that of last three is 35, the fourth number is :
Answers
Let the 6 numbers be a,b,c,d,e, and f
Average =
Average = Sum of the data/Total no. of data
So, according to the Question ,
(a + b + c + d + e + f)/6 = 30
=> a + b + c + d + e + f = 180 ...eq.01
Now average of First Four Number is 25
=> ( a + b + c + d)/4 = 25
=> a + b + c + d = 100 ...eq.02
also given that average of last three numbers is 35
=> (d + e + f)/3 = 35
=> d + e + f = 105
=> e + f = 105 - d ...eq.03
In eq. 01,
a + b + c + d + e + f = 180
=> (a + b + c + d) + 105 - d = 180 (from eq.03)
=> 100 + 105 - d = 108 [from eq. 02]
=> 205 - d = 108
=> - d = - 97
=> d = 97
Hence the fourth number is 97 (ANS)
Step-by-step explanation:
Let the 6 numbers be a,b,c,d,e, and f
Average =
Average = Sum of the data/Total no. of data
So, according to the Question ,
(a + b + c + d + e + f)/6 = 30
=> a + b + c + d + e + f = 180 ...eq.01
Now average of First Four Number is 25
=> ( a + b + c + d)/4 = 25
=> a + b + c + d = 100 ...eq.02
also given that average of last three numbers is 35
=> (d + e + f)/3 = 35
=> d + e + f = 105
=> e + f = 105 - d ...eq.03
In eq. 01,
a + b + c + d + e + f = 180
=> (a + b + c + d) + 105 - d = 180 (from eq.03)
=> 100 + 105 - d = 108 [from eq. 02]
=> 205 - d = 108
=> - d = - 97
=> d = 97
Hence the fourth number is 97 (ANS)