Math, asked by Taaj8096, 1 year ago

The average of the first five multiples of 9 is:
A.20
B.27
C.28
D.30

Answers

Answered by Jiyakhera
2
hey mate !!!❤✌
here ur ans ⤵⤵

➡ let's know the first 5 multiples of 9
they are :- 9,18,36,45&54

now let's calculate it's mean :-
formula = sum of observations ÷ No of observations
insert values in this formula
= 9+18+27+36+45+54/5
=189/5
= 37.8

 \boxed{ans = 37.8}


⭐ hope it helps ⭐
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Jiyakhera: na !!!
Jiyakhera: ya *
Jiyakhera: hmm!! now i cant edit it
Jiyakhera: hey taj8096.... i am solving it here as it can't edit my ans .... 9+18+27+36+45/5 = 135/5 = 27 so ur ans is 27
Answered by anurag432
0

Answer:

Option B.

The average of the first five multiples of 9 is equal to 27.

Step-by-step explanation:

The first five multiples of 9 are

9 × 1 = 9

9 × 2 = 18

9 × 3 = 27

9 × 4 = 36

9 × 5 = 45

9,18,27,36,45 are the first five multiples of 9.

Average= sum of observations ÷ No of observations.

sum of observations = 9 + 18 + 27 + 36 + 45

sum of observations = 135

No of observations = 5

Average = 135 ÷ 5 = 27

Therefore the average of the first five multiples of 9 is 27.

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