Question

The average of the numbers 1, 2, 3,................. 98, 99 and 'x' is 100x. Find the value of x?

Answer 1

S=$\frac{n(n+1)}{2}$
S=$\frac{99(99+1)}{2}$
S=4950

4950/99=50(average of 1+2+3+....+98+99)
$\frac{50+x}{2}$=100x
50+x=200x
199x=50
x=0.25