Question

The average of three equally spaced numbers is 12. If the largest number equals twice the smallest, what is the value of the smallest number? * 6 4 8 10 12

Answer 1

Answer:

I hope it will help you...

Answer 2

Therefore the smallest number is 8

Step-by-step explanation:

The average of three equally spaced number is 12.

The largest number equals twice the smallest number.

Let the smallest number be x

Then the largest number is = 2x

The difference between largest and smallest number is = 2x-x = x

Therefore the common difference is =$\frac{x}{2}$

So the middle number is =(x+$\frac{x}{2}$) $=\frac{3x}{2}$

According to the problem,

x+$\frac{3x}{2}$+2x= 12×3

⇔$\frac{9x}{2} =36$

⇔x =8

Therefore the smallest number is 8