Question

The average of two numbers is 62. If 2 is added to the smallest number, the ratio between the numbers becomes 1:2. The difference of the number is?

Answer 1

LET THE BIGGER NO. BE x and the smaller one be y
eq. 1)  x+y/2=62 so, x+y = 124
& eq. 2) x/y+2 = 1/2 so, by cross multiplication 2x=y+2 (eq. 3) 
by eq3. x = y+2/2
by putting this value of x in eq. 1, we get
y+2/2 + y= 124
y+2+2y/2 = 124
y+2+2y = 248
3y = 248-2= 246 
therefore, y = 246/3 = 82
and x= 124- 82= 42
& x-y = 82-42=40
HOPE IT HELPED

Answer 2

Answer:

44

Step-by-step explanation:

We are given that The average of two numbers is 62.

Let the smaller number be x

Let the larger number be y

So, $Average = \frac{\text{Sum of all observations}}{\text{Number of observations}}$

$62 = \frac{x+y}{2}$

$124 = x+y$

$124-x= y$

Thus the smaller number = x

The larger number = 124-x

Now we are given that If 2 is added to the smallest number, the ratio between the numbers becomes 1:2.

$\frac{x+2}{124-x}=\frac{1}{2}$

$2(x+2)=124-x$

$2x+4=124-x$

$3x=120$

$x=40$

Thsu the smaller number is 40

So, larger number = 124-40= 84

Now the difference between the smaller number and the larger number = 84-40=44.

Hence The difference of the number is 44.