Question

The average speed of the bob of a seconds pendulum is 2 m/s. Determine the
(a) linear amplitude
(b) frequency of oscillation.​

Answer 1

$\Large\underline{\underline{\sf Given:}}$

• The average speed of the bob of a seconds pendulum is 2 m/s

$\Large\underline{\underline{\sf To\:Find:}}$

• Linear Amplitude
• Frequency of Oscillation

$\Large\underline{\underline{\sf Solution:}}$

✧✦✧(a) Linear Amplitude :

Here is seconds pendulum i.e. time period of this pendulum is 2 seconds.

⛬ The Lenght of pendulum is 1m

${\boxed{\sf Average\:Speed=\dfrac{Total\: Distance}{Total\:Time} }}$

Distance = Average Speed × Time

⠀⠀⠀⠀⠀⠀= 2 × 2

⠀⠀⠀⠀⠀⠀= 4m

$\Large{\sf Amplitude=\dfrac{Distance}{4}}$

$\implies{\sf \dfrac{4}{4}}$

$\implies{\sf 1m }$

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✧✦✧(b) Frequency of Oscillation

$\large{\boxed{\sf \pink{Frequency=\dfrac{1}{Time}} }}$

$\implies{\sf \dfrac{1}{2} }$

$\implies{\sf 0.5\:Hz }$

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$\Large\underline{\underline{\sf Answer:}}$

⛬ Linear Amplitude (A) = 1m

⠀Frequency of Oscillation (f) = 0.5 Hz

Answer 2

Answer:

amplitude=1m

frequency =0.5Hz