Question

the average square of first 10 natural number is

Answer 1

Solution:

Sum of Square of First 10 natural Number

${1}^{2} + {2}^{2} + {3}^{2} .... + {10}^{2} \\ = \frac{10(10 + 1)(2 \times 10 + 1)} {6} \\ = \frac{10 \times 11 \times 21}{6} \\ = 35 \times 11 = 385$
Average = 385/10 = 38.5 Ans.

Answer 2

1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2 + 7^2 + 8^2 + 9^2 + 10^2
= 1+4+9+16+25+36+49+64+81+100
=385
the average = 385/10
= 38.5 ans