Question

The average velocity of an ideal gas molecule at 273K is 0.3 . The average velocity at 1200K will be

Answer 1

Answer:

27°C = 300 K

927°C = 1200 K

Average velocity ∝ sqrt(Absolute Temperature)

v1 / v2 = sqrt(T1 / T2)

0.3 / v = sqrt(300 / 1200)

0.3 / v = 1 / 2

v = 0.6 m/s

Average velocity at 927°C is 0.6 m/s

Answer 2

Answer:

1.3186

Explanation:

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