The axis of symmetry for the graph of the function f start bracket x end bracket equals one-quarter x square plus b x plus 10 is x=6. What is the value of b?
−12
−3
3
Answers
Value of b = -3 if The axis of symmetry for the graph of the function f(x) = x²/4 + bx + 10 is 6
Step-by-step explanation:
f(x) = x²/4 + bx + 10
The axis of symmetry for the graph of the function is 6
so root would be
6 + a & 6 - a
Sum of Roots = 6 + a + 6 - a = 12
Sum of roots = - b/a = -b/(1/4) = - 4b
-4b = 12
=> b = -3
Value of b = -3
Value of b = -3 if The axis of symmetry for the graph of the function f(x) = x²/4 + bx + 10 is 6
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Answer:
value of b=-3 if the axis o symmetry for the graph of the function f(x)=x^2/4+bx+10 is 6
Explanation:
f(x)=x^2/4+bx+10
The axis of symmetry for the graph of the function of 6.
So root would be 6+0 and 6-a
Sum of roots=6+a+6-a=12
Sum of roots=-b/a=-b(1/4)=-4b
-4b=12
● b= -3
value of b=-3 if the function f(x)=x^2/4+bx+10 is 6.